2r^2+3r-8+4r^2-5r+2=2r^2+3r-8+4r^2-5r+2

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Solution for 2r^2+3r-8+4r^2-5r+2=2r^2+3r-8+4r^2-5r+2 equation: 



2r^2+3r-8+4r^2-5r+2=2r^2+3r-8+4r^2-5r+2

We move all terms to the left:

2r^2+3r-8+4r^2-5r+2-(2r^2+3r-8+4r^2-5r+2)=0

We add all the numbers together, and all the variables

6r^2-(2r^2+3r-8+4r^2-5r+2)-2r-6=0

We get rid of parentheses

6r^2-2r^2-4r^2-3r+5r-2r+8-2-6=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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